How can you use trigonometric functions to simplify # 9 e^( ( 3 pi)/8 i ) # into a non-exponential complex number?
1 Answer
Jan 23, 2016
# 9 [ cos((3pi)/8) + isin((3pi)/8 ) ]#
Explanation:
Euler's theorem states :
#e^(itheta) = costheta + isintheta # in this question
# theta =(3pi)/8 #
# rArr = 9[ cos((3pi)/8) + isin((3pi)/8) ] #
