How can you use trigonometric functions to simplify # 3 e^( ( pi)/8 i ) # into a non-exponential complex number?
1 Answer
Feb 23, 2016
Explanation:
Using
#color(blue)" Euler's relation" # which states:
#re^(itheta) = r(costheta + isintheta ) # here r = 3 and
#theta = pi/8 #
#rArr 3e^(pi/8i) = 3(cos(pi/8) + isin(pi/8))#
