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How can you use trigonometric functions to simplify # 27 e^( ( pi)/2 i ) # into a non-exponential complex number?

1 Answer

Dec 24, 2015

Use the equation #e^(itheta) = cos(theta)+isin(theta)# to find
#27e^(pi/2i) = 27i#

Explanation:

Using the identity #e^(itheta) = cos(theta) + isin(theta)# we have

#27e^(pi/2i) = 27(cos(pi/2)+isin(pi/2))#

#= 27(0 + i(1))#

#= 27i#

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