How can you use trigonometric functions to simplify # 24 e^( ( 5 pi)/3 i ) # into a non-exponential complex number?
1 Answer
Mar 2, 2016
Explanation:
Using
#color(blue) " Euler's relationship " # which states
# re^(thetai) = r[costheta + isintheta] # here r = 24 and
#theta = (5pi)/3 #
#rArr 24e^((5pi)/3 i) = 24 [ cos((5pi)/3) + isin((5pi)/3) ] #
