How can you use trigonometric functions to simplify # 2 e^( ( 5 pi)/3 i ) # into a non-exponential complex number?
1 Answer
Mar 15, 2016
Explanation:
Using Euler's identity , which states :
# re^(theta i) = r ( costheta + isintheta )# here r = 2 and
# theta = (5pi)/3 #
# rArr 2e^(5pi/3 i) = 2[cos((5pi)/3) + isin((5pi)/3) ] #
