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How can you use trigonometric functions to simplify # 17 e^( ( 13 pi)/12 i ) # into a non-exponential complex number?

1 Answer

Apr 5, 2016

#17 cos ((13pii)/12)+17i sin((13pii)/12)#

or # -16.420739046913- 4.399923766751i#

Explanation:

#17e^((13pii)/12)# is equivalent to#17 cos ((13pii)/12)+17i sin((13pii)/12)#
which gives

-16.420739046913- 4.399923766751.i

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