How can you use trigonometric functions to simplify # 15 e^( ( pi)/2 i ) # into a non-exponential complex number?

Question

How can you use trigonometric functions to simplify # 15 e^( ( pi)/2 i ) # into a non-exponential complex number?

1 Answer

Impact of this question

1136 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-01-09T16:58:05

I found #15e^(pi/2i)=15[cos(pi/2)+isin(pi/2)]=15[0+i]=15i#

Explanation:

You can convert it into a complex number in trigonometric form first remembering that:
#rhoe^(thetai)=rho[cos(theta)+isin(theta)]#
In your case:
#15e^(pi/2i)=15[cos(pi/2)+isin(pi/2)]=15[0+i]=15i#

Science

Math

Humanities

... and beyond

How can you use trigonometric functions to simplify # 15 e^( ( pi)/2 i ) # into a non-exponential complex number?

1 Answer

Explanation:

Related questions

Impact of this question