How can you use trigonometric functions to simplify # 15 e^( ( pi)/2 i ) # into a non-exponential complex number?

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How can you use trigonometric functions to simplify # 15 e^( ( pi)/2 i ) # into a non-exponential complex number?

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Answer 1 · 2016-01-09T16:58:05

I found #15e^(pi/2i)=15[cos(pi/2)+isin(pi/2)]=15[0+i]=15i#

Explanation:

You can convert it into a complex number in trigonometric form first remembering that:
#rhoe^(thetai)=rho[cos(theta)+isin(theta)]#
In your case:
#15e^(pi/2i)=15[cos(pi/2)+isin(pi/2)]=15[0+i]=15i#

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How can you use trigonometric functions to simplify # 15 e^( ( pi)/2 i ) # into a non-exponential complex number?

1 Answer

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