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How can you use trigonometric functions to simplify # 14 e^( ( pi)/8 i ) # into a non-exponential complex number?

1 Answer

Oct 27, 2016

The complex number is #14(cos(pi/8)+isin(pi/8))#

Explanation:

Let #z# be the complex number

So #z=14e^(ipi/8)#

We use #z=re^(itheta)=r(costheta+isintheta)#

So #r=14# and #theta=pi/8#

#z=14(cos(pi/8)+isin(pi/8))#

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