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How can you use trigonometric functions to simplify # 12 e^( ( pi)/2 i ) # into a non-exponential complex number?

1 Answer

Jun 14, 2016

#12 e^{pi/2i} = 12 i#

Explanation:

Using Moivre`s relationship

#e^{i theta} = cos(theta)+i sin(theta)#

#12 e^{pi/2i} = 12(cos(pi/2)+i sin(pi/2)) = 12 i#

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