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How can you use trigonometric functions to simplify # 12 e^( ( 19 pi)/12 i ) # into a non-exponential complex number?

1 Answer

Apr 19, 2018

#3sqrt6-3sqrt2-i(3sqrt6+3sqrt2)#

Explanation:

We can turn into #re^(itheta)# into a complex number by doing: #r(costheta+isintheta)#

#r=12#, #theta=(19pi)/12#

#12(cos((19pi)/12)+isin((19pi)/12))#

#3sqrt6-3sqrt2-i(3sqrt6+3sqrt2)#

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