Since the y values are given for x=1, 2, 3, 4 let us write the y values as a sequence, then form the difference of those terms, then the difference of the differences...
Notice that it takes 2 steps to get to a constant sequence, so this is a quadratic.
Next, let us construct the y value for x=0 by adding in a column on the left...
We do this by writing in another 4 on the last row, then calculating 9 as 13 - 4, then calculating 58 as 67 - 9.
Now we have added this row for x=0 we can use its values to find the equation of the quadratic...
f(x) = color(red)(58) + color(red)(9) * (x)/(1!) + color(red)(4) * (x(x-1))/(2!)=58+7x+2x^2
=2x^2+7x+58