# How can you best describe the transfer of heat that occurs when 1.40 mol of H_2 reacts?

Nov 19, 2016

Well, you can start by specifying with what reagent the dihydrogen reacts.

#### Explanation:

I think (and I acknowledge I might be wrong) that you refer to a combustion reaction:

${H}_{2} \left(g\right) + \frac{1}{2} {O}_{2} \left(g\right) \rightarrow {H}_{2} O \left(l\right) + \Delta$

Now I know for a fact that DeltaH^@""_f(H_2O)=-285*kJ*mol^-1

And thus if $1.4 \cdot m o l$ $\text{dihydrogen}$ react with $0.7 \cdot m o l$ $\text{dioxygen}$ we get out $1.4 \cdot m o l \times \left(- 285\right) \cdot k J \cdot m o {l}^{-} 1 \cong 400 \cdot k J$