How can the strength of an electric field be quantified?

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Answer 1 · 2018-03-09T10:15:26

$E = \frac{V}{d} = \frac{F}{Q_{2}} = \frac{k Q_{1}}{r^{2}}$ $E=V/d=F/Q_2=(kQ_1)/r^2$ , where:

$E$ $E$ = Electric field strength ( $N C^{- 1} or V m^{- 1}$ $NC^-1 or Vm^-1$ )
$V$ $V$ = electric potential
$d$ $d$ = distance from the point charge ( $m$ $m$ )
$F$ $F$ = Electrostatic force ( $N$ $N$ )
$Q_{1} and Q_{2}$ $Q_1 and Q_2$ = charge on objects $1$ $1$ and $2$ $2$ ( $C$ $C$ )
$r$ $r$ = distance from point charge ( $m$ $m$ )
$k$ $k$ = $\frac{1}{4 π ε_{0}} = 8.99 \cdot 10^{9} N m^{2} C^{- 2}$ $1/(4piepsilon_0)=8.99*10^9Nm^2C^-2$
$ε_{0}$ $epsilon_0$ = permittivity of free space ( $8.85 \cdot 10^{- 12}$ $8.85*10^-12$ $F m^{- 1}$ $Fm^-1$ )