How can I simplify #(2n)/(4n^(1/2))#?

1 Answer
mason m
Dec 14, 2015

#sqrtn/2#

Explanation:

First, simplify the constants.

#n/(2n^(1/2))#

Now, use the rule that #a^b/a^c=a^(b-c)#.

Therefore, #n/(2n^(1/2))=n^1/(2n^(1/2))=n^(1-1/2)/2=n^(1/2)/2#.

Note that #n^(1/2)=sqrtn#, so the expression can also be written as #sqrtn/2#.

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