How to find x? If y=x^2-4x

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How to find x? If y=x^2-4x

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Answer 1 · 2017-05-18T15:13:49

$x = 0 or x = 4$ $x=0" or " x=4$

Explanation:

$to solve equate to zero and factorise$ $" to solve equate to zero and factorise"$

$\Rightarrow x^{2} - 4 x = 0$ $rArrx^2-4x=0$

$\Rightarrow x (x - 4) = 0 \leftarrow common factor of x$ $rArrx(x-4)=0larrcolor(blue)" common factor of x"$

$now equate each factor to zero$ $"now equate each factor to zero"$

$that is x = 0 or x - 4 = 0$ $"that is " x=0" or " x-4=0$

$\Rightarrow x = 0$ $rArrx=0$

$\Rightarrow x - 4 = 0 \Rightarrow x = 4$ $rArrx-4=0rArrx=4$

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How to find x? If y=x^2-4x

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