H=2A/B+b for B?

1 Answer
Mar 5, 2017

See the entire solution process below:

Explanation:

First, subtract #color(red)(b)# from each side of the equation to isolate the #B# term while keeping the equation balanced:

#H - color(red)(b) = (2A)/B + b - color(red)(b)#

#H - b = (2A)/B + 0#

#H - b = (2A)/B#

Now, multiply each side of the equation by #color(red)(B)/color(blue)(H - b)# to solve for #B#:

#color(red)(B)/color(blue)(H - b) xx (H - b) = color(red)(B)/color(blue)(H - b) xx (2A)/B#

#color(red)(B)/cancel(color(blue)(H - b)) xx color(blue)(cancel(color(black)((H - b)))) = cancel(color(red)(B))/color(blue)(H - b) xx (2A)/color(red)(cancel(color(black)(B)))#

#B = (2A)/(H - b)#