Given $theta = (19pi) / 6$ how do you find $sintheta$ ?

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Answer 1 · 2015-07-25T04:54:09

Find $sin ((19pi)/6)$

Ans: $-1/2$

On the trig unit circle,

$sin ((19pi)/6) = sin ((7pi)/6 + (12pi)/6) = sin ((7pi)/6 + 2pi) =$

$= - sin ((pi)/6) = - 1/2$

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Given theta = (19pi) / 6theta = (19pi) / 6 how do you find sinthetasintheta?