Given the function G(x) = 1/3 (12-x) what is x when G(x) = -7?

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Given the function G(x) = 1/3 (12-x) what is x when G(x) = -7?

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Answer 1 · 2018-06-10T20:35:24

$x = 33$ $x=33$

Explanation:

$given g (x) = \frac{1}{3} (12 - x) and g (x) = - 7$ $"given "g(x)=1/3(12-x)" and "g(x)=-7$

$we can equate the right sides$ $"we can equate the right sides"$

$\frac{1}{3} (12 - x) = - 7$ $1/3(12-x)=-7$

$4 - \frac{1}{3} x = - 7$ $4-1/3x=-7$

$- \frac{1}{3} x = - 7 - 4 = - 11$ $-1/3x=-7-4=-11$

$multiply both sides by - 3$ $"multiply both sides by "-3$

$- 3 \times - \frac{1}{3} x = - 3 \times - 11$ $-3xx-1/3x=-3xx-11$

$\Rightarrow x = 33$ $rArrx=33$

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Given the function G(x) = 1/3 (12-x) what is x when G(x) = -7?

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