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Given the equation: #2Al + 3Cu_2 ->2Al^(3+) + 3Cu#. What is the reduction half-reaction?

1 Answer

Jun 10, 2017

#Cu^(2+) + 2e^(-) rarr Cu(s)#

Explanation:

And the oxidation reaction.........

#Al(s) rarr Al^(3+) + 3e^-#

And cross-multiplying to remove the electrons.........

#2Al(s) + 3Cu^(2+) rarr 2Al^(3+) + 2Cu(s)#

Is charge balanced? Is mass balanced?

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