Given that $log (a) 2 = x$ $log(a)2 = x$ , find $log (a) 2 a$ $log(a)2a$ in terms of $x$ $x$ ?

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Given that $log (a) 2 = x$ $log(a)2 = x$ , find $log (a) 2 a$ $log(a)2a$ in terms of $x$ $x$ ?

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Answer 1 · 2017-09-13T14:28:31

$x + 1$ $x+1$

Explanation:

$using the laws of logarithms$ $"using the "color(blue)"laws of logarithms"$

$∙ x log x + log y \Leftrightarrow log (x y)$ $•color(white)(x)logx+logyhArrlog(xy)$

$∙ x {log}_{a} (a) = 1$ $•color(white)(x)log_a(a)=1$

$\Rightarrow {log}_{a} (2 a) = {log}_{a} (2) + {log}_{a} (a)$ $rArrlog_a(2a)=log_a(2)+log_a(a)$

$\times \times \times \times = x + 1$ $color(white)(xxxxxxxx)=x+1$

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Given that $log (a) 2 = x$ $log(a)2 = x$ , find $log (a) 2 a$ $log(a)2a$ in terms of $x$ $x$ ?

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