Given $sin30^circ=1/2$ and $tan30^circ=sqrt3/3$ , how do you find $cot30^circ$ ?

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Answer 1 · 2016-12-10T12:05:58

$cot30^o=sqrt3$

As $cotA=1/tanA$ ,

$cot30^o=1/(tan30^o)=1/(sqrt3/3)$

i.e. $cot30^o=1×3/sqrt3=(sqrt3)^2/sqrt3=sqrt3$ .

Note that we do not need $sin30^o=1/2$ .

Given sin30^circ=1/2sin30^circ=1/2 and tan30^circ=sqrt3/3tan30^circ=sqrt3/3, how do you find cot30^circcot30^circ?