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Given #sin30^circ=1/2# and #tan30^circ=sqrt3/3#, how do you find #cos30^circ#?

1 Answer

Jan 20, 2017

The answer is #=sqrt3/2#

Explanation:

We use

#tantheta=sintheta/costheta#

#sin30º=1/2#

#tan30º=sqrt3/3#

#cos30º=(sin30º)/(tan30º)=(1/2)/(sqrt3/3)=(1/2)/(1/sqrt3)=sqrt3/2#

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