Given $sectheta=5$ and $tantheta=2sqrt6$ , how do you find $cot(90^circ-theta)$ ?

Question

2622 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-12-25T10:22:00

$cot(90^@-theta)=2sqrt6$

As $cot(90^@-theta)=tantheta$

$cot(90^@-theta)=2sqrt6$

Note there is no need to use $sectheta=5$

Given sectheta=5sectheta=5 and tantheta=2sqrt6tantheta=2sqrt6, how do you find cot(90^circ-theta)cot(90^circ-theta)?