Given: $p (x) = - 5 | x | + | - x + 1 |$ $p(x) = -5absx + abs(-x + 1$ , $h (x) = - x^{2} - 3 x$ $h(x) = -x^2 - 3x$ , and $g (x) = 5 - \sqrt{x + 30}$ $g(x) = 5 - sqrt(x+30)$ , how do you find h(4)?

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Answer 1 · 2015-05-24T15:37:07

h(4)= $- {(4)}^{2} - 3 (4) = - 16 - 12 = - 28$ $-(4)^2 -3(4)=-16-12=-28$
You just need to write 4 instead of x in the equation.

Given: p(x) = -5absx + abs(-x + 1p(x)=−5|x|+|−x+1|p(x) = -5absx + abs(-x + 1, h(x) = -x^2 - 3xh(x)=−x2−3xh(x) = -x^2 - 3x, and g(x) = 5 - sqrt(x+30)g(x)=5−√x+30g(x) = 5 - sqrt(x+30), how do you find h(4)?