Given log4=0.6021, log9=0.9542, and log12=1.-792, how do you find log 4.096?

1 Answer
Shwetank Mauria
Jan 13, 2017

#log4.096=0.6126#

Explanation:

#log4.096#

= #log4096/1000#

= #log4096-log1000#

and as factors of #4096=2xx2xx2xx2xx2xx2xx2xx2xx2xx2xx2xx2=2^12=4^6#

= #log4^6-3#

= #6log2-3#

= #6xx0.6021-3#

= #3.6126-3#

= #0.6126#

Note: We do not need #log9=0.9542#, and #log12=1.0792#. Further, if you check you will find #log4.096=0.6124#. The difference is due to rounding off.

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