Given log_b 2= 0.3562, log_b 3=0.5646, and log_b 5=0.8271, how do you evaluate log_b15?

1 Answer
Daniel L.
May 13, 2016

log_b15=1.3917

Explanation:

To calculate log_b15 we use the formula log_ba*c=log_ba+log_bc

First we have to write 15 as a product of numbers 2,3 and 5. Number 2 will not be used because 15 is an odd number, but we can write that 15=3*5

Now we can use the formula above to write the logarythm as a sum of 2 given values.

log_b15=log_b3*5=log_b3+log_b5=0.5646+0.8271=1.3917

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