Given $f(x)=x+2, g(x)=x-3, h(x)=x+4$ how do you determine $y=(f(x))/(h(x))times(g(x))/(h(x))$ ?

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Answer 1 · 2017-07-01T11:16:13

$y = frac(x^(2) - x - 6)(x^(2) + 8 x + 16)$

We have: $y = frac(f(x))(h(x)) times frac(g(x))(h(x))$

$Rightarrow y = frac(f(x) times g(x))((h(x))^(2))$

Let's substitute the expressions for $f(x)$ , $g(x)$ and $h(x)$ into the equation:

$Rightarrow y = frac((x + 2) times (x - 3))((x + 4)^(2))$

Then, let's expand the parentheses:

$Rightarrow y = frac(x^(2) + 2 x - 3 x - 6)(x^(2) + 4 x + 4 x + 16)$

$therefore y = frac(x^(2) - x - 6)(x^(2) + 8 x + 16)$

Given f(x)=x+2, g(x)=x-3, h(x)=x+4f(x)=x+2, g(x)=x-3, h(x)=x+4 how do you determine y=(f(x))/(h(x))times(g(x))/(h(x))y=(f(x))/(h(x))times(g(x))/(h(x))?