Given $f(x)=x+2, g(x)=x-3, h(x)=x+4$ how do you determine $y=(f(x)g(x))/(h(x))$ ?

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Answer 1 · 2017-02-05T08:21:49

$(x^2-x-6)/(x+4)$

You simply would substitute and then do all the operations:

$y=(color(red)(f(x))color(green)(g(x)))/color(blue)(h(x))$

$=(color(red)((x+2))color(green)((x-3)))/color(blue)((x+4))$

$=(x^2-3x+2x-6)/(x+4)$

$=(x^2-x-6)/(x+4)$

Given f(x)=x+2, g(x)=x-3, h(x)=x+4f(x)=x+2, g(x)=x-3, h(x)=x+4 how do you determine y=(f(x)g(x))/(h(x))y=(f(x)g(x))/(h(x))?