Given $f (x) = x + 2, g (x) = x - 3, h (x) = x + 4$ $f(x)=x+2, g(x)=x-3, h(x)=x+4$ how do you determine $y = \frac{f (x) g (x)}{h (x)}$ $y=(f(x)g(x))/(h(x))$ ?

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Answer 1 · 2017-02-05T08:21:49

$\frac{x^{2} - x - 6}{x + 4}$ $(x^2-x-6)/(x+4)$

You simply would substitute and then do all the operations:

$y = \frac{f (x) g (x)}{h (x)}$ $y=(color(red)(f(x))color(green)(g(x)))/color(blue)(h(x))$

$= \frac{(x + 2) (x - 3)}{(x + 4)}$ $=(color(red)((x+2))color(green)((x-3)))/color(blue)((x+4))$

$= \frac{x^{2} - 3 x + 2 x - 6}{x + 4}$ $=(x^2-3x+2x-6)/(x+4)$

$= \frac{x^{2} - x - 6}{x + 4}$ $=(x^2-x-6)/(x+4)$

Given f(x)=x+2,g(x)=x−3,h(x)=x+4f(x)=x+2, g(x)=x-3, h(x)=x+4 how do you determine y=f(x)g(x)h(x)y=(f(x)g(x))/(h(x))?