Given $f (x) = 3 x^{2} + 2, g (x) = \sqrt{x + 4}, h (x) = 4 x - 2$ $f(x)=3x^2+2, g(x)=sqrt(x+4), h(x)=4x-2$ how do you determine the combined function $y = (h - g) (x)$ $y=(h-g)(x)$ and state its function?

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Answer 1 · 2018-02-26T22:14:47

$(h - g) (x) = 4 x - 2 - \sqrt{x + 4}$ $(h-g)(x)=4x-2-sqrt(x+4)$

$y = (h - g) (x) = h (x) - g (x)$ $y=(h-g)(x)=h(x)-g(x)$

To find this, simply subtract $g (x)$ $g(x)$ from $h (x)$ $h(x)$ :

$g (x) = \sqrt{x + 4}$ $g(x)=sqrt(x+4)$ , $h (x) = 4 x - 2$ $h(x)=4x-2$

$h (x) - g (x) = 4 x - 2 - \sqrt{x + 4}$ $h(x)-g(x)=4x-2-sqrt(x+4)$

Given f(x)=3x2+2,g(x)=√x+4,h(x)=4x−2f(x)=3x^2+2, g(x)=sqrt(x+4), h(x)=4x-2 how do you determine the combined function y=(h−g)(x)y=(h-g)(x) and state its function?