Given $f(x) = 2x^2+3$ and g(x) = 5x+2, how do you find $(3f(2) - 2g(2) ) / (f(1) + g(1) )$ ?

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Given $f(x) = 2x^2+3$ and g(x) = 5x+2, how do you find $(3f(2) - 2g(2) ) / (f(1) + g(1) )$ ?

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Answer 1 · 2017-04-15T08:51:42

$3/4$

Explanation:

$f(color(red)(1))=2(color(red)(1))^2+3=2+3=5$

$f(color(red)(2))=2(color(red)(2))^2+3=8+3=11$

$g(color(magenta)(1))=5(color(magenta)(1))+2=5+2=7$

$g(color(magenta)(2))=5(color(magenta)(2))+2=10+2=12$

$"Substituting values into expression"$

$rArr((3xx11)-(2xx12))/(5+7)$

$=(33-24)/12$

$=9/12$

$=3/4$

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Given $f(x) = 2x^2+3$ and g(x) = 5x+2, how do you find $(3f(2) - 2g(2) ) / (f(1) + g(1) )$ ?

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Given $f(x) = 2x^2+3$ and g(x) = 5x+2, how do you find $(3f(2) - 2g(2) ) / (f(1) + g(1) )$ ?