Given f(x)= -2sin x, g(x)= sin 2x, how do you graph h(x)= (f+g)(x)?

1 Answer
Leland Adriano Alejandro
Feb 16, 2016

I can show how it looks like..

Explanation:

the graph of #f(x)=-2sin x# alone
graph{((y+2*sin x))=0[-6,6,-3,3]}

the graph of #g(x)=sin 2x#
graph{((y-2sin xcos x))=0[-6,6,-3,3]}

the graph of #f(x)# and #g(x)# together in one coordinate system
graph{((y+2sin x)(y-2sin x*cos x))=0[-6,6,-3,3]}

the graph of #h(x)=(f+g)(x)=-2sin x+sin 2x#
graph{((y+2sin x)+(y-2sin x*cos x))=0[-6,6,-3,3]}

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