Given $cosalpha=1/3$ , how do you find $secalpha$ ?

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Answer 1 · 2017-02-10T11:21:28

You should get $3$

You know that:
$sec(alpha)=1/(cos(alpha))$
substitute your value for $cos(alpha)$ to get the result.

Given cosalpha=1/3cosalpha=1/3, how do you find secalphasecalpha?