Given #cosalpha=1/3#, how do you find #cotalpha#?

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Given #cosalpha=1/3#, how do you find #cotalpha#?

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Answer 1 · 2016-12-19T14:40:31

#sqrt2/4#

Explanation:

#cos t = 1/3#. Find sin t.
#sin^2 t = 1 - cos^2 t = 1 - 1/9 = 8/9 #--> #sin t = +- (2sqrt2)/3#
Since cos t = 1/3, t is in Quadrant I, then sin t is positive.

#cot t = cos t/(sin t) = (1/3)(3/(2sqrt2))= 1/(2sqrt2) = (sqrt2)/4#.

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Given #cosalpha=1/3#, how do you find #cotalpha#?

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