Four cells each of internal resistance 1 ohm and e.m.f. 1.9v are connected to a external resistance of 18 ohm. find the terminal potential difference of this combination?

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Answer 1 · 2017-08-24T14:32:17

The potential difference is $= 6.22 V$ $=6.22V$

We apply the equation

$U = R I$ $U=RI$

$E - U = r I$ $E-U=rI$

$E = (R + r) I$ $E=(R+r)I$

The emf is $E = 4 \cdot 1.9 = 7.6 V$ $E=4*1.9=7.6V$

The total resistance is

$r+R=4*1+18=22Omega$

The current is

$I=7.6/22=0.35A$

So, the potential difference is

$=U=18*0.35=6.22V$