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For what values of x, if any, does #f(x) = 1/((x-3)(x-2)) # have vertical asymptotes?

1 Answer

Aug 22, 2016

#x=3 & 2#

Explanation:

#f(x)# is undefined or approaches infinity when the denominator is zero.

In this case, for a zero denominator:
Either factor #(x-3)# or factor #(x-2)# equals to zero.

Hence #x=3&2# will give you vertical asymptotes.

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