For what values of x, if any, does #f(x) = 1/((2x+3)(x-6) # have vertical asymptotes?
1 Answer
May 21, 2016
x=6 and x= -3/2
Explanation:
For vertical asymptotes, put the denominator=0,that means (2x+3)(x-6)=0. Hence it is x=6 and x= -3/2
The graph of the function would make it clear
