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For what values of x, if any, does #f(x) = 1/((2x-2)(5x-4) # have vertical asymptotes?

1 Answer

Jun 22, 2016

#x=1# or #x = 4/5#

Explanation:

you will have vertical asymptotes when you have a zero in the denominator, ie when you are dividing by zero.

here that occurs when # 2x - 2 = 0# and #5x - 4 = 0# ie when #x=1# or #x = 4/5#

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