For the given vector: v = 3i - j + 2k, how do you write a unit vector in the direction of vector v?

1 Answer
George C.
Jul 16, 2016

v/(|| v ||) = 3/sqrt(15)i-1/sqrt(15)j+2/sqrt(15)k

Explanation:

|| v || = sqrt(3^2+(-1)^2+2^2) = sqrt(9+1+4) = sqrt(15)

So the normalised vector in the direction of v is:

v/(|| v ||) = 1/(sqrt(15)) (3i-j+2k) = 3/sqrt(15)i-1/sqrt(15)j+2/sqrt(15)k

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