For the equation $v_f^2=v_i^2 + 2ad$ , how do you solve for $v_i$ ?

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Answer 1 · 2015-06-29T13:21:41

You isolate $v_i^2$ on one side and take the square root from both sides of the equation.

The equation

$v_f^2 = v_i^2 + 2*a*d$ , where

$v_f$ - the final speed;
$v_i$ - the initial speed;
$a$ - the acceleration of an object;
$d$ - its displacement.

establishes a relationship between an accelerating object's initial and final speeds and the total displacement.

So, to solve for $v_i$ , simply isolate $v_i^2$ on one side of the equation

$v_i^2 = v_f^2 - 2 * a * d$

then take the square root from both sides of the equation

$sqrt(v_i^2) = sqrt(v_f^2 - 2 * a * d)$

$v_i = sqrt(v_f^2 - 2 * a * d)$

For the equation v_f^2=v_i^2 + 2adv_f^2=v_i^2 + 2ad, how do you solve for v_iv_i?