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For #F(x) = -4x# how do you find (6)?

↳Redirected from "How do I solve #y'' + y = -2 sin(x)# with the initial conditions #y(0) = 0# and #y'(0) = 1#?"

1 Answer

Feb 27, 2017

See the entire solution process below:

Explanation:

For each #color(red)(x)# in the function #F(x)# substitute #color(red)(6)#:

#F(color(red)(x)) = -4color(red)(x)# becomes:

#F(color(red)(6)) = -4 xx color(red)(6)#

#F(color(red)(6)) = -24#

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