For a first order reaction the value of rate constant for the reaction $A (g) \to 2 B (g) + C (s)$ $A(g) -> 2B(g) + C(s)$ ?

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Answer 1 · 2017-11-23T16:54:14

$Rate = k[A]$ $"Rate = k[A]"$

$A_{(g)} \to 2 B_{(g)} + C_{(s)}$ $A_((g)) -> 2B_((g)) + C_((s))$

From Rate Law, Rate of the above reaction is expressed as

$Rate = k {[A]}^{x}$ $"Rate" = k[A]^x$

It’s first order reaction so, $x = 1$ $x = 1$

$Rate = k [A]$ $"Rate" = k[A]$

For a first order reaction the value of rate constant for the reaction A(g) -> 2B(g) + C(s)A(g)→2B(g)+C(s)A(g) -> 2B(g) + C(s)?