Find the value of x36x2+6x when x=2+223+213?

1 Answer
Jun 20, 2018

2

Explanation:

x36x2+6x

=x36x2+12x86x+124

=(x2)36(x2)4

After setting y=x2, this equation became y36y4

Hence,

y=223+213

y3=4+6223+6213+2

y3=6+6(223+213)

y3=6y+6

y36y4=2