Find the radius and center of the equation #x^2+y^2+6x-8y=0#?

Related questions

• How do you translate a graph to the left or right?
• How do you translate a graph up or down?
• What does it mean to translate a graph?
• If the equation of a conic section is #(x-3)^2/49+(y-4)^2/13=1#, how has its center been translated?
• If the equation of a conic section is #(x+6)^2/81-(y+1)^2/16=1#, how has its center been translated?
• If the equation of a conic section is #(x-2)^2+(y+5)^2=25#, how has its center been translated?
• What is the difference between the graph of #y=2x^2+3x-4# and the graph of #y=2(x-4)^2+3(x-4)-4#?
• Where is the center of the graph of #(x+3)^2+(y-2)^2=4#?
• How do use the method of translation of axes to sketch the curve #x^2+y^2-4x+3=0#?
• How do use the method of translation of axes to sketch the curve #x^2+y^2+2x-6y+6=0#?