Find instantaneous rate of $6 cos (3 x) + 2$ $6cos(3x)+2$ where $x = 5$ $x=5$ in radians?

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Find instantaneous rate of $6 cos (3 x) + 2$ $6cos(3x)+2$ where $x = 5$ $x=5$ in radians?

How do you find instantaneous rate of $6 cos (3 x) + 2$ $6cos(3x)+2$ where $x = 5$ $x=5$ in radians.

Please no calculus solutions, but from this equation: $\frac{△ f (x)}{△ x}$ $(trianglef(x))/(triangle x)$

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Answer 1 · 2017-12-05T00:24:14

So I got the answer key today, so I will answer myself, maybe for future references for others.

Explanation:

$\frac{△ f (x)}{△ x} = \frac{[6 cos (3 \cdot 5.01)] - [6 cos (3 \cdot 4.99)]}{5.01 - 4.99}$ $(triangle f(x))/(triangle x)= [[6cos(3*5.01)]-[6cos(3*4.99)]]/(5.01-4.99)$

$\frac{△ f (x)}{△ x} = ~ \frac{- 2.6731108 - (- 2.43904)}{0.02}$ $(triangle f(x))/(triangle x)=~ [-2.6731108- (-2.43904)]/(0.02)$

$\frac{△ f (x)}{△ x} = ~ - 11.7$ $(triangle f(x))/(triangle x)=~ -11.7$

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Find instantaneous rate of $6 cos (3 x) + 2$ $6cos(3x)+2$ where $x = 5$ $x=5$ in radians?

How do you find instantaneous rate of $6 cos (3 x) + 2$ $6cos(3x)+2$ where $x = 5$ $x=5$ in radians.

Please no calculus solutions, but from this equation: $\frac{△ f (x)}{△ x}$ $(trianglef(x))/(triangle x)$

1 Answer

Explanation:

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Find instantaneous rate of 6cos(3x)+26cos(3x)+2 where x=5x=5 in radians?

How do you find instantaneous rate of 6cos(3x)+26cos(3x)+2 where x=5x=5 in radians. Please no calculus solutions, but from this equation: △f(x)△x(trianglef(x))/(triangle x)

1 Answer

Explanation:

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Find instantaneous rate of $6 cos (3 x) + 2$ $6cos(3x)+2$ where $x = 5$ $x=5$ in radians?

How do you find instantaneous rate of $6 cos (3 x) + 2$ $6cos(3x)+2$ where $x = 5$ $x=5$ in radians.

Please no calculus solutions, but from this equation: $\frac{△ f (x)}{△ x}$ $(trianglef(x))/(triangle x)$