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#F( x ; b) = log_b(x+1/log_b(x+1/log_b(x+...))), x>=b>1.#How do you approximate F(15, 10)=1.19958, nearly?

1 Answer

Aug 3, 2016

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Explanation:

From

#y = log_b(x+1/y)# and calling #b = z# the surface

#G(x,y,z) = z^y-x-1/y = 0# for

#( (-5 < x < 5), (-5 < y < 5), (0< z < 5))#

locally, has the aspect below

enter image source here

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