Exponential and Logarithmic Equations. Solve the equation 3.6045log(s)=log(m)-3.4425 if s is 0.56.?

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Answer 1 · 2018-01-24T22:25:56

$m \approx 342.6444826$ $m~~342.6444826$

I am assuming these are common logs ( base 10 )

$3.6045 log (s) = log (m) - 3.4425$ $3.6045log(s)=log(m)-3.4425$

If $s = 0.56$ $s=0.56$

$3.6045 log (0.56) = log (m) - 3.4425$ $3.6045log(0.56)=log(m)-3.4425$

$3.6045 log (0.56) + 3.4425 = log (m)$ $3.6045log(0.56)+3.4425=log(m)$

Taking antilogarithms of both sides:

$10^{3.6045 log (0.56) + 3.4425} = m$ $10^(3.6045log(0.56)+3.4425)=m$

$:.$

$m~~342.6444826$