Emilio invests $1,000 at 7.5% compounded quarterly. How long, to the nearest month will take for the investment to grow to $1,500? Algebra Linear Equations Percent Equations 1 Answer Binayaka C. May 26, 2017 #$1000# will take #5# years #6# months to grow to #$1500# Explanation: Let it be #n# years. Given : #P=1000 , F=1500 , r= 7.5%#(quarterly) # :. r/400= 0.01875 # . Formula #F=P* (1+r/400)^(4*n) # # :.1500 = 1000(1+.01875)^(4n) or (1.01875)^(4n)= 1500/1000 # or # (1.01875)^(4n)= 1.5 #. Taking log on both sides we get, #4nlog(1.01875) = log (1.5) or 4n = log (1.5)/log(1.01875) # or #4n= 21.8269:. n =5.4567# year. #:. n=5.4567# years or #5# years #5# months #14# days #$1000# will take #5# years #6# months to grow to #$1500# [Ans] Answer link Related questions Jimmy made a #"75%# on a test worth #46# points. How many points did he get correct? How do you use proportions to solve percent equations? How do you translate percent problems into an equation? What number is 32% of 600? What number is #3/4#% of 16? 8 is 20% of what number? 99 is 180% of what number? What percent of 7.2 is 45? What percent of 150 is 5? What is 2% of 92? See all questions in Percent Equations Impact of this question 2081 views around the world You can reuse this answer Creative Commons License