Could the points (-4,3), (-1,1) and (1,3) form the vertices of a right triangle?

1 Answer
bp
Dec 11, 2016

No

Explanation:

Using distance formula sqrt((x_2-x_1)^2 +(y_2 -y_1)^2), the distance between (-4,3) and (-1,1) would be sqrt(3^2 +(-2)^2)=sqrt13, distance between (-1,1) and (1,3) would be sqrt(2^2 +2^2)= sqrt 8, and the distance between (-4,3) and (1,3) would be sqrt(5^2 +0^2)=sqrt25

Now the sum of the squares of any of these two distances does not equal to the square of the the third distance. Hence the triangle is not a right triangle.

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