Could someone help me to do the mentioned equation,please?
e^(2ln(tan5x))=?
1 Answer
Dec 4, 2017
Explanation:
"assuming you require the derivative"
"note that "e^lnx=x
rArre^(2ln(tan5x))=e^(ln(tan5x)^2)=(tan5x)^2
"differentiate using the "color(blue)"chain rule"
"given "y=f(g(x))" then "
dy/dx=f'(g(x))xxg'(x)larrcolor(blue)"chain rule"
d/dx((tan5x)^2)
=2tan5x xxd/dx(tan5x)
=2tan5xsec^2 5x xxd/dx(5x)
=10tan5xsec^2 5x
