Convert 345 moles of $"H"_2"O"$ to molecules?

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Answer 1 · 2018-02-27T21:48:43

Using Avogadro's number, the total number of $"H"_2"O"$ molecules is $2.08*10^26$ .

Avogadro's number relates the total amount of atoms/molecules contained in a mole of some element/compound:

$"1 mol element" = 6.022*10^23 " atoms"$

OR

$"1 mol compound" = 6.022*10^23 " molecules"$

We can then use stoichiometry to calculate the total number of molecules:

$"345 mol H"_2"O" * (6.022*10^23 "molecules H"_2"O")/("1 mol H"_2"O") = 2.08 *10^26 " molecules H"_2"O"$

Convert 345 moles of "H"_2"O""H"_2"O" to molecules?